4x^2-80x-372=0

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Solution for 4x^2-80x-372=0 equation:



4x^2-80x-372=0
a = 4; b = -80; c = -372;
Δ = b2-4ac
Δ = -802-4·4·(-372)
Δ = 12352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12352}=\sqrt{64*193}=\sqrt{64}*\sqrt{193}=8\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-8\sqrt{193}}{2*4}=\frac{80-8\sqrt{193}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+8\sqrt{193}}{2*4}=\frac{80+8\sqrt{193}}{8} $

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